Answer:Part 1) The measure of angle A is [tex]A=80\°[/tex]Part 2) The length side of a is equal to [tex]a=10.9\ units[/tex]Part 3) The length side of b is equal to [tex]b=6.3\ units[/tex]Step-by-step explanation:step 1Find the measure of angle Awe know thatThe sum of the internal angles of a triangle must be equal to 180 degreesso[tex]A+B+C=180\°[/tex]substitute the given values[tex]A+35\°+65\°=180\°[/tex][tex]A+100\°=180\°[/tex][tex]A=180\°-100\°=80\°[/tex]step 2Find the length of side aApplying the law of sines[tex]\frac{a}{sin(A)}=\frac{c}{sin(C)}[/tex]substitute the given values[tex]\frac{a}{sin(80\°)}=\frac{10}{sin(65\°)}[/tex][tex]a=\frac{10}{sin(65\°)}(sin(80\°))[/tex][tex]a=10.9\ units[/tex]step 3Find the length of side bApplying the law of sines[tex]\frac{b}{sin(B)}=\frac{c}{sin(C)}[/tex]substitute the given values[tex]\frac{b}{sin(35\°)}=\frac{10}{sin(65\°)}[/tex][tex]b=\frac{10}{sin(65\°)}(sin(35\°))[/tex][tex]b=6.3\ units[/tex]